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Sample Problems and Solutions
Let there by 'x' chickens and 'y' pigs. Therefore, x + y = 200 --- (equation #1) Each chicken has 2 legs and each pig has 4 legs Therefore, 2x + 4y = 540 --- (equation #2) Solving equations #1 and #2, we get x = 130 and y = 70.
Let x be the age of the son three years ago,then the age of his father three years ago is x + 24,thus their present age is x + 3 for the son and x + 27 for the father, using the second premise of the problem, the father is 5 time as old as his son, we have an equation based on the present age, x + 27 = 5(x + 3), solving for x we have x = 3, which is the age of the son three years ago and the present age of the son is 6 years old thus the the son's age three years from now is 9 years old.
For the two systems with no solution the systems should be inconsistent system, meaning the there is no intersection between the two line or they are parallel to each other, if two lines are parallel their slopes must be the same. the slope of 3x + 4y = 12 is m1 = - 3/4 and the slope of kx + 12 y = 30 is m2 = - k/12, since m1 = m2, then - 3/4 = - k/12, solving for k = 9
Using D = rt, the rate of the train in meters per second (Transform the rate to m/s = 7200 m / 3600 seconds = 20 m/s) is 20 m/s to find for the total number of seconds the train pass the flatform we have to subtract the total number of time the train crosses the flatform and the time the man is standing on the flatform, that is 30 - 18 = 12, thus the length of the flatform is 20(12) = 240 meters
Change the rate of the train and motorbike to mps, we have 10000 m / 3600 s = 27.78 mps for the train and 64000m / 3600 s = 17.78 mps for the motorbike, using the principle of overtaking, distance travelled by the train must be equal to the distance travelled by the motorbike, that is DTrain = Dmotorbike, the distance travelled by the train is D = (27.78)(40) = 1111.2 meters and the distance travelled by the motorbike is D = (17.78)(40) = 711.2, and since the distance travelled by the train and the motorbike must be the same, to get for the length of the train, we have 1111.2 - 711.2 = 400 meters, thus the length of the train is 400 meters.
Solving=for the average speed of Jim using partial distance travelled, 3(60) = 180 and 5(24) = 120, the total distance travelled is 180 + 120 = 300 m divided by the total number of hours which is 3 + 5 = 8, thus the average speed of Jim is 300 m divided by 8 hours = 37.5 mph
1,105 - (10 + 20 + 15) = 1,060, and since the ratio after the deduction is 11:18:24, we have an equation 11x + 18x + 24x = 1060 and x = 20, thus Charlie received 24(20) = 480 + 15 = 495
Since Mary and Mike invest 700 and 300 respectively the total number of investment is P1000, let x be the rate of the investment and using the formula I = PRT, the total profit is equal to I = (1000)(x)(1) = 1000x and 1/3 of that is 1000x/3 and divided to them equally we have 1000x / 6 and the remaining 2/3 of 1000x is divided by the ratio between the investments of each that is 1000x (7/15) for Mary and 1000x (1/5) for Mike, since Mary received 800 more than Mike we have an equation (1000x / 6) + 1000x (7/15) = (1000x / 6) + 1000x (1/5) + P800, solve for x = 3, thus the total profit is 3000.
The ratio is 1:2, using the guess and check strategy we have 20%(1) + 50%(2) = 40%(1 + 2), 1.2 = 1.2
To have two real roots and distinct roots the discriminant of the quadratic function must be greater than zero, that is b2 - 4ac > 0, thus (- 6)2 - 4(1)(k) > 0, the k < 9, thus the highest integral value for k is 8.
Since 1.5 is a root of the quadratic equation, substituting it to the equation (1.5)2 + 1.5 m + 24 = 0, solving for m we have - 17.5
To have a real root and equal the discriminant must be equal to zero, that is b2 - 4ac = 0, then m2 - 4(1)(4) = 0, m2 = 16, taking the square root we have m = - 4, and + 4